Javascript program to check odd-even number

Check Even and Odd numbers using an if-else statement.

The logic of the code is:
If the number % 2 is equal to 0 then it is even number else it is odd number.

let number = 4;
if(number % 2 == 0)
  {
    console.log("Even number");
  }
else
  {
    console.log("Odd number");
  }

The output of the code is

Even number

Let’s take input from the user.

let number = prompt("Enter the number:");
if(number % 2 == 0)
  {
    console.log("Even number");
  }
else
  {
    console.log("Odd number");
  }

The output of the code is

Enter the number: 5
Odd number

Enter the number: 8
Even number

Even and odd numbers using the Ternary operator.

let number = prompt("Enter the number:");
const res = (number % 2 == 0)? "Even number" : "odd number";
console.log(res)

The output of the code is

Enter the number:4
Even number

Enter the number:9
Odd number

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