How to find odd and even numbers from 1 to 100 in Javascript.

In this code, we are going to find the odd and even number from 1 to 100 in Javascript. To understand this you need to know about the for loop and if-else statement.
We will divide the code into three programs.

The logic of the code is:
If the number % 2 == 0 then it is an even number else it is an odd number.

How to find Odd numbers from 1 to 100 in Javascript.

for(let i = 1; i <= 100; i++ )
  {
    if(i % 2 != 0)
      {
        console.log(i)
      }
  }

The output of the code is

1 3 5 7... upto 99

How to find Even numbers from 1 to 100 in Javascript.

for(let i = 1; i <= 100; i++ )
  {
    if(i % 2 == 0)
      {
        console.log(i)
      }
  }

The output of the code is

2,4,6,8.... upto 96,98, 100

How to find both odd and even numbers.

for(let i = 1; i <= 100; i++ ) 
  {
    if(i % 2 == 0)
      {
        console.log(i+" is Even number")
      }
    else
    {
      console.log(i+" is Odd number")
    }
  }

The output of the code is

"1 is Odd number"
"2 is Even number"
"3 is Odd number"
"4 is Even number"
"5 is Odd number"
"6 is Even number"
.
.
"96 is Even number"
"97 is Odd number"
"98 is Even number"
"99 is Odd number"
"100 is Even number"